Kinetics

5.2.1 Force, Traction and Stress Vectors

38 There are two kinds of forces in continuum mechanics body forces: act on the elements of volume or mass inside the body, e.g. gravity, electromagnetic fields. dF = pbdVol.

surface forces: are contact forces acting on the free body at its bounding surface. Those will be defined in terms of force per unit area.

39 The surface force per unit area acting on an element dS is called traction or more accurately stress vector.

Most authors limit the term traction to an actual bounding surface of a body, and use the term stress vector for an imaginary interior surface (even though the state of stress is a tensor and not a vector).

40 The traction vectors on planes perpendicular to the coordinate axes are particularly useful. When the vectors acting at a point on three such mutually perpendicular planes is given, the stress vector at that point on any other arbitrarily inclined plane can be expressed in terms of the first set of tractions.

41 A stress, Fig 5.1 is a second order cartesian tensor, Oj where the 1st subscript (i) refers to the direction of outward facing normal, and the second one (j) to the direction of component force.

Oil

O12

O13

t1

a = Oij =

O21

O22

O 23

=

t2

O31

O32

O33

t3

42 In fact the nine rectangular components aj of a turn out to be the three sets of three vector components (an , a12 ,a13), (a21 , a22, a23), (a3i ,a32 ,a33) which correspond to the three tractions ti, t2 and t3 which are acting on the x1 ,x2 and x3 faces (It should be noted that those tractions are not necesarily normal to the faces, and they can be decomposed into a normal and shear traction if need be). In other words, stresses are nothing else than the components of tractions (stress vector), Fig. 5.2.

43 The state of stress at a point cannot be specified entirely by a single vector with three components; it requires the second-order tensor with all nine components.

Figure 5.1: Stress Components on an Infinitesimal Element

X1 Stresses as components of a traction vector (Components of a tensor of order 2 are vectors)

X1 Stresses as components of a traction vector (Components of a tensor of order 2 are vectors)

Figure 5.2: Stresses as Tensor Components

5.2.2 Traction on an Arbitrary Plane; Cauchy's Stress Tensor

44 Let us now consider the problem of determining the traction acting on the surface of an oblique plane (characterized by its normal n) in terms of the known tractions normal to the three principal axis, ti, t2 and t3. This will be done through the so-called Cauchy's tetrahedron shown in Fig. 5.3, and will be obtained without any assumption of equilibrium and it will apply

X

(-K

2 *

3 /

>

A

2s

*\7

Figure 5.3: Cauchy's Tetrahedron in fluid dynamics as well as in solid mechanics.

45 This equation is a vector equation, and the corresponding algebraic equations for the components of tn are

tni

= Oiim + cr2i n2 + cr31n3

tjU2

= a\2n\ + (722«'2 + Cr32rc3

tn3

= cr13m + 0-23^2 + & 3317-3

Indicial notation

tni

= CTjiUj

dyadic notation

tn

46 We have thus established that the nine components aij are components of the second order tensor, Cauchy's stress tensor.

Example 5-1: Stress Vectors if the stress tensor at point P is given by a =

We seek to determine the traction (or stress vector) t passing through P and parallel to the plane ABC where A(4,0,0), B(0, 2,0) and C(0,0,6). Solution:

The vector normal to the plane can be found by taking the cross products of vectors AB and AC:

ei

e2

e3

N = ABxAC=

-4

2

0

(5.41

-4

0

6

= 12ei + 24e2 + 8e3 The unit normal of N is given by

Hence the stress vector (traction) will be

5.2.3 Invariants

47 The principal stresses are physical quantities, whose values do not depend on the coordinate system in which the components of the stress were initially given. They are therefore invariants of the stress state.

48 When the determinant in the characteristic Equation is expanded, the cubic equation takes the form

where the symbols Ia, IIa and IIIa denote the following scalar expressions in the stress components:

Ia

= 0"ii + 022 + 033 = aü = tr a

(5.45)

IIa

= -(011022 + 022 033 + 033 011 ) +

222 °23 + °31 + 012

(5.46)

1 1

2

(5.47)

= ~~ aii(Tjj) = 2 G'i3(7'i3 ~

(5.48)

IIIa

= detCT = —&ijk.€-pqr(Jip(Jjq(Jkr

(5.49)

49 In terms of the principal stresses, those invariants can be simplified into

Ia

= °(1) + °(2) + 0(3)

(5.50)

IIa

= -(0(1)0(2) + °(2)0(3) + 0(3)0(1) )

(5.51)

IIIa

= ^(1)^(2)^(3)

(5.52)

5.2.4 Spherical and Deviatoric Stress Tensors

50 If we let a denote the mean normal stress p

a = -p= — (cru + cr22 + CT33J = ~gu = -tr a then the stress tensor can be written as the sum of two tensors:

Hydrostatic stress in which each normal stress is equal to —p and the shear stresses are zero. The hydrostatic stress produces volume change without change in shape in an isotropic medium. _

Deviatoric Stress: which causes the change in shape.

G11 — G

G12

G13

Gdev —

g 21

G22 — g

g 23

g 31

G32

5.2.5 Stress Transformation

51 From Eq. 5.22 and 5.23, the stress transformation for the second order stress tensor is given by

Gip = aj aq&n in Matrix Form [g] = [A]t[ct] [A] (5.56)

(Tjq — Q'iQ'pO'ip in Matrix Form [a] = [A][ct][A]t (5.57)

For the 2D plane stress case we rewrite Eq. 5.25

5.2.6 Polar Coordinates

It is often necessary to express cartesian stresses in terms of polar stresses and vice versa. This can be done through the following relationships

Gxy = (orr — gqq) sin 6 cos 6 + aro(cos2 6 — sin2 6)

3a4 4a

cos 26

3a4 4a2'

yy a sin 26

3a4 2a

cos 26

3a4 2a

0 0

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